27^2+48^2=c^2

Solution for 27^2+48^2=c^2 equation:

27^2+48^2=c^2

We move all terms to the left:

27^2+48^2-(c^2)=0

We add all the numbers together, and all the variables

-1c^2+3033=0

a = -1; b = 0; c = +3033;
Δ = b2-4ac
Δ = 02-4·(-1)·3033
Δ = 12132
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{12132}=\sqrt{36*337}=\sqrt{36}*\sqrt{337}=6\sqrt{337}$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{337}}{2*-1}=\frac{0-6\sqrt{337}}{-2}
=-\frac{6\sqrt{337}}{-2}
=-\frac{3\sqrt{337}}{-1}
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{337}}{2*-1}=\frac{0+6\sqrt{337}}{-2}
=\frac{6\sqrt{337}}{-2}
=\frac{3\sqrt{337}}{-1}
$